How to Read Many Switches with One MCU Pin

Have you ever been chugging away at a project(s) and the project keeps growing and growing, while you add more things to it (we call that a Feaping Creaturism)? On a recent project, I was building a frequency meter and added a five function signal generator/frequency synthesizer. I soon wound up with more switches than I had available pins left, so what’s a guy to do?
However, I soon had seven more switches on my Funbox (yeah, that’s what I called my function generator…I know, I have no creativity) and here’s a short instructable showing you how you can do the same. It doesn’t require any shift registers or specific IC’s. In fact, it doesn’t require a microcontroller, either, if discrete semiconductors is how you roll.
Here’s one way you can read/manage multiple switches using a single pin on your AVR (or other microcontroller…I’ve heard there are other microcontrollers besides AVR‘s, but I can’t imagine…)
How to Read Many Switches
Step 1 The Essentials
In order to accomplish this, you’ll need a few components. It helps to have a multitude of switches that you have to manage. You’ll also need some resistors and either a microcontroller that has ADC (Analog-to-Digital Conversion) or some other way you’d like to indicate that there was a switch activated and which switch it was.
If you wanted you could use a voltage controlled oscillator to indicate this, maybe with some blinken lights, or alternatively, with sound. In this ‘ible, I’m going to pretend we’re using an AVR, but in your world you can pretend whatever makes you happy. I miss Bob Ross.
Step 2 The Voltage Divider
The Voltage Divider
Essentially, the way we’re going to do this is by using a technique and circuit called a voltage divider.  Voltage dividers do, as you may have guessed, divide the V,,in,, voltage by some value that you determine.  You can divide voltage with several components, including capacitors and inductors, but here I’m going to do it with the good ‘ol resistor.

The Idea

What we are doing is putting two components in series that will cause, each individually, a drop in voltage across the component.  Look at the first picture if I’m not making sense.  There is a potential difference of 9V from rail to rail.  Between 9V and 0V there are two resistors in series.  Each of these will experience a voltage drop across itself, depending on the resistance, as you probably recall from V = IR.  If you take a voltage measurement between the two resistors, you’ll get some value between 9V and 0V, depending on how much voltage has dropped across the first resistor and how much is left to drop over the 2nd resistor, before 0V.
There is a straightforward formula for calculating the voltage drop across a resistor in this situation and it looks like this.  Let the voltage over resistor 1 (R1) be V1 and the voltage over resistor two (R2) be V2.
Since I can’t use formatting anymore, look at picture 2 below for the formula…
So, in our resistive divider, the Vout voltage can be determined by our formula for V2 (since we’ll be referencing GND to 0V).
What does this have to do with having a bunch of switches being detected from one pin?  Well, turn the page and I’ll show you!
For more details, click: How to Read Many Switches with One MCU Pin

About The Author

Ibrar Ayyub

I am an experienced technical writer holding a Master's degree in computer science from BZU Multan, Pakistan University. With a background spanning various industries, particularly in home automation and engineering, I have honed my skills in crafting clear and concise content. Proficient in leveraging infographics and diagrams, I strive to simplify complex concepts for readers. My strength lies in thorough research and presenting information in a structured and logical format.

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